(2x-1)^2+x(1-2x)=4x^2-1

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Solution for (2x-1)^2+x(1-2x)=4x^2-1 equation:



(2x-1)^2+x(1-2x)=4x^2-1
We move all terms to the left:
(2x-1)^2+x(1-2x)-(4x^2-1)=0
We add all the numbers together, and all the variables
(2x-1)^2+x(-2x+1)-(4x^2-1)=0
We multiply parentheses
-2x^2+(2x-1)^2+x-(4x^2-1)=0
We get rid of parentheses
-2x^2-4x^2+(2x-1)^2+x+1=0
We add all the numbers together, and all the variables
-6x^2+x+(2x-1)^2+1=0
We move all terms containing x to the left, all other terms to the right
-6x^2+x+(2x-1)^2=-1

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